For the PV diagram shown, for path 1-2-3, 100 J of heat is …

Physics Thermodynamics Mix MCQ (Single Correct)

For the PV diagram shown, for path 1-2-3, 100 J of heat is given to the system and 40 J of work is done by the system. For path 1-4-3 the work done by system is 10 J. Then -

U 3 – U 1 = 60 joule , where U 3 & U 1 are internal energy of gas

for path 3 → 1 the heat is rejected and equal to 85 joule

for path 1 → 4 the work done by system is 10 joule

for path 1 → 4 the heat given to system is 20 joule

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(a, b, c)

Path – 1,2,3,

Δ Q = Δ U + Δ W, 100 = Δ U + 40

Δ U = 60 joule = U 3 – U 1

Path 1 – 4W by gas = W by gas 1-4-3 = 10 joule W for process 3 → 1 = + 10 = 25 joule

Q = – 25 – 60 = – 85 joule

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